Asked by Didid
If 96g SO2 is added to 2 moles of oxygen at STP,calculate the volume of SO3 that is formed
Answers
Answered by
DrBob222
This is a limiting reagent problem.
2SO2 + O2 ==> 2SO3
How many mols SO2 do you have in 96 g. That's
mols = grams/molar mass = 96/64 = 1.5
1 mol SO2 produces 1 mol SO3 so you will get 1.5 mols SO3 IF there is enough oxygen.
From the equation 1 mol O2 will produce 2 mol SO3 so 2 mol O2 will produce 4 mols SO3. The LR is SO2 so you will get 1.5 mols SO3. 1 mol will occupy 22.4 L@ STP. So 1.5 mol SO3 @ STP will occupy .........L.
2SO2 + O2 ==> 2SO3
How many mols SO2 do you have in 96 g. That's
mols = grams/molar mass = 96/64 = 1.5
1 mol SO2 produces 1 mol SO3 so you will get 1.5 mols SO3 IF there is enough oxygen.
From the equation 1 mol O2 will produce 2 mol SO3 so 2 mol O2 will produce 4 mols SO3. The LR is SO2 so you will get 1.5 mols SO3. 1 mol will occupy 22.4 L@ STP. So 1.5 mol SO3 @ STP will occupy .........L.
Answered by
Bofelo
Getting answers
Answered by
Qhayiya
Calculate the mass and volume 2SO²+O²=2SO³
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