Asked by Anon
A car passed a point on a course at exactly 12 noon and maintained a speed of 60 km/h. A second car passed the same point 1 hour later, followed the same course, and maintained a speed of 100km/h. When, and after what distance from this point, would the second car have caught up to the first car?
Answers
Answered by
Reiny
time passed since the second car passed the check point ---- t hours
distance covered by first car = 60 + 60t
distance covered by the 2nd car = 100t
they are equal, take it from there
distance covered by first car = 60 + 60t
distance covered by the 2nd car = 100t
they are equal, take it from there
Answered by
Anon
Thank you, Reiny.
Answered by
henry2,
d1 = d2,
60 * T = 100 *(T-1),
60T = 100T - 100,
T = 2.5 h.
d = 60*T = 60*2.5 = 150 km.
60 * T = 100 *(T-1),
60T = 100T - 100,
T = 2.5 h.
d = 60*T = 60*2.5 = 150 km.
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