Asked by David Cameron
A 8kg mass rests on an inclined plane. If the limiting frictional force of 50N and g=10m/s2, then the angle of inclination of the plane is?
Answers
Answered by
henry2,
M*g = 8 * 10 = 80 N.
Fp = 80*sin A = Force parallel with the incline.
Fp - Fs = M*a,
80*sinA - 50 = 8 * 0,
80*sinA - 50 = 0,
A = 38.7 deg.
Fs = Force of static friction.
Fp = 80*sin A = Force parallel with the incline.
Fp - Fs = M*a,
80*sinA - 50 = 8 * 0,
80*sinA - 50 = 0,
A = 38.7 deg.
Fs = Force of static friction.
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