Question

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 68.1 person at 37.1 oC immerses in 50.2 kg of water at 40.5o C, the equilibrium temperature is 38.7 oC. What is the specific heat of the person? Use 4.186 kJ/kgoC for the specific heat of water. Answer to 3 significant figures in kJ/kgoC .

Answer 1

Heat out of water = 4.186 * 50.2 * (40.5 - 38.7)
Heat into Joe Sore = x * 68.1 * (38.7 - 37.1)

set them equal and solve for x