Asked by peace
In a Gp the product of the second and the fourth term is double the fifth term and the sum of the first four term is 80. Find the first five terms of the Gp
Answers
Answered by
Reiny
Using your definitions of a GP ....
"the product of the second and the fourth term is double the fifth term "
---> (ar)(ar^3) = 2(ar^4)
a^2 r^4 = 2a r^4
a = 2
"the sum of the first four term is 80"
---> a + ar + ar^2 + ar^3 = 80
2(1 + r + r^2 + r^3) = 80
1 + r + r^2 + r^3 - 40 = 0
r^3 + r^2 + r - 39 = 0
Try ±3 and ± 13
sure enough , r = 3 satisfies the equation
did a long division and got
r^3 + r^2 + r - 39 = (r-3)(r^2 + 4r + 13)
The quadratic does not have any real roots, so r = 3
take it from there.
"the product of the second and the fourth term is double the fifth term "
---> (ar)(ar^3) = 2(ar^4)
a^2 r^4 = 2a r^4
a = 2
"the sum of the first four term is 80"
---> a + ar + ar^2 + ar^3 = 80
2(1 + r + r^2 + r^3) = 80
1 + r + r^2 + r^3 - 40 = 0
r^3 + r^2 + r - 39 = 0
Try ±3 and ± 13
sure enough , r = 3 satisfies the equation
did a long division and got
r^3 + r^2 + r - 39 = (r-3)(r^2 + 4r + 13)
The quadratic does not have any real roots, so r = 3
take it from there.
Answered by
Anonymous
explain
Answered by
divine
how did u do the long division please?
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