Asked by mssailormouth

A weight of 15 N is located at a distance of 2.5 meters from the fulcrum of a simple lever. At what distance from the fulcrum should a weight of 20.0 N be placed on the opposite side of the fulcrum to balance the system?

Answered by R_scott
15 N * 2.5 m = 20.0 N * ?
Answered by mssailormouth
1.875 so about 1.9m
Answered by Darren
15N is applied at a distance of 2.5m
Answered by Live GOOD
how many cm away should 20 N be placed? you only show M
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