Asked by Justin

Imagine a boat that travels at 3.0 m/s in still water. (a) In which direction should the boat point its bow to travel directly across a 0.50-km wide river when the river flows at 1.5 m/s? (b) What is the time interval for the trip, expressed in minutes?
This seems easy but I honestly have no idea how to do this. Please help.
Answered by bobpursley
Draw a vector diagram. Theta=arcsin(3/5). That will give the resulatant directly across.
time interval: speed across: 3*sinTheta
time= distance/speed= 500m/3sinTheta = ....seconds
Answered by henry2,
a. Vr = Vb + Vc = Vb + (-1.5i) = 3.0 m/s = Resultant velocity.
Vb = 3 + 1.5i = 3.35m/s[26.6o]. N. of E.

b. d = V * T = 500 m.
3 * T = 500,
T = 166.667 s. = 2.78 min.
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