Asked by Damilare
The bearing of point A and B from a common point c are 030 and 290 respectively.find the bearing of a from b ,if a and b are equidistance from c
Answers
Answered by
bobpursley
Isn't it a triangle in which two legs are the same length, and the attached angles equal?
angleAB=290 to 360 + 000 to o3o= 70+30=100 deg
so the sum of the other two equal angles is 180-100=80
so each of those angles ....
angleAB=290 to 360 + 000 to o3o= 70+30=100 deg
so the sum of the other two equal angles is 180-100=80
so each of those angles ....
Answered by
oobleck
Since the distance doesn't matter, set C at (0,0) and let CB=CA=100
Now you just want to find the slope of the line from B to A. That will be the cotangent of the bearing angle.
A = (50,87)
B = (-94,34)
see what you can do with that.
Now you just want to find the slope of the line from B to A. That will be the cotangent of the bearing angle.
A = (50,87)
B = (-94,34)
see what you can do with that.
Answered by
Anonymous
What is the final answer
Answered by
Patricia
I cant solve it
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.