Asked by Andrew
You will need a binomial table for n = 20 for this problem. Suppose that a quiz consists of 20 True-False questions. A student hasn't studied for the exam and will just randomly guesses at all answers (with True and False equally likely). What is the probability that the student will get less than 10 right?
Answers
Answered by
R_scott
(w + r)^20 ... p(wrong) = p(right) = 0.5
the 11th term is ... 20C10 w^10 r^10 = 0.1762
... the answer is the sum of the 1st ten terms
the total probability (sum of all terms) is 1
half of the "center" term is ... 0.0881
sum of the 1st ten terms is ... 0.5 - 0.0881
the 11th term is ... 20C10 w^10 r^10 = 0.1762
... the answer is the sum of the 1st ten terms
the total probability (sum of all terms) is 1
half of the "center" term is ... 0.0881
sum of the 1st ten terms is ... 0.5 - 0.0881
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.