Asked by mssailormouth
A 12000 kg train engine moving at 2.2 m/s locks into 3 boxcars with a total mass of 25000 kg sitting still. If the collision is inelastic and has little friction, how fast will the engine and cars move?
I got 1.4 but correct answer is 0.71?
I don't understand how
12000x2.2 +25000x0 =26400
12000+25000=37000/26400
=1.4
I got 1.4 but correct answer is 0.71?
I don't understand how
12000x2.2 +25000x0 =26400
12000+25000=37000/26400
=1.4
Answers
Answered by
R_scott
momentum is conserved
(12000 * 2.2) + (25000 * 0) = (12000 + 25000) * v
(12000 * 2.2) + (25000 * 0) = (12000 + 25000) * v
Answered by
mssailormouth
so I should set this up at initialV=combined and divided by the combined mass
That's where I'm messing it up.
thanks
That's where I'm messing it up.
thanks
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.