Asked by sarah
ESPN has a new show called Super Smack: When Giants Collide! On the first episode, the World's largest bowling ball (Mbb=1200 kg) moving to the right with a speed of 3.0 m/s, collides head-on (in a perfectly inelastic collision) with the World's Largest Ball of Wax (Mwax=240 kg) which is moving to the left with a speed of 5.0 m/s. Determine the motions of the two balls after the collision (Assume both balls are moving horizontally without air resistance; also, this problem does not involve rolling.)
PLEASE HELP and show all work physics is my worst subject
PLEASE HELP and show all work physics is my worst subject
Answers
Answered by
bobpursley
conservation of momentum
Mbb*Vbb + Mwax*Vwax= (Mwax+Mbb)*Vfinal solve for Vfinal.
Note velocity signs: if to the right is +, then to the left is -
Mbb*Vbb + Mwax*Vwax= (Mwax+Mbb)*Vfinal solve for Vfinal.
Note velocity signs: if to the right is +, then to the left is -
Answered by
henry2,
Given: M1 = 1200 kg, V1 = 3 m/s,
M2 = 240kg, V2 = -5 m/s.
V3 = Velocity of M1 and M2 after collision.
Momentum before = Momentum after,
M1*V1 + M2*V2 = M1*V3 + M2*V3,
1200*3 + 240*(-5) = 1200V3 + 240*V3,
V3 = ?.
M2 = 240kg, V2 = -5 m/s.
V3 = Velocity of M1 and M2 after collision.
Momentum before = Momentum after,
M1*V1 + M2*V2 = M1*V3 + M2*V3,
1200*3 + 240*(-5) = 1200V3 + 240*V3,
V3 = ?.