Asked by No_pyz
A light fixture that weighs 82.2 N is hung symmetrically by three cables that make an angle of 67.1 degrees with the horizontal. Determine the tension (in Newtons) in one of the cables.
Answers
Answered by
R_scott
draw a diagram
[m * g * (1/3) ] / (tension) = sin(67.1ยบ)
[m * g * (1/3) ] / (tension) = sin(67.1ยบ)
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