Asked by Joan
the angle of elevation of the top of a radio mast from a point due east of it and 96m away from its base is 30degrees. from another point due west of the mast, the angle of elevation of the top is 60degrees. calculate the distance of the second point from the base of the mast
Answers
Answered by
oobleck
Draw a diagram. If the height is h, then on the east side
h/96 = tan30°
On the west side, if the observation point is at distance x, then
h/x = tan60°
So, x = (96 tan30°)/(tan60°) = 32m
h/96 = tan30°
On the west side, if the observation point is at distance x, then
h/x = tan60°
So, x = (96 tan30°)/(tan60°) = 32m
Answered by
David
Pls help me draw the diagram
Answered by
samson
d workings
Answered by
Chiagoziem
Please the diagram
Answered by
Anonymous
No diagram👎
Answered by
Elizabeth
Thank u so much
But where's the diagram??????
But where's the diagram??????
Answered by
Bahd guy
Please Where Is The Diagram And I Dont understand The Calculation
Answered by
Lily
Please draw the diagram
Answered by
Lily
Please the diagram
Answered by
Aduragbemi
Pls d diagram
Answered by
ENIOLA
Thank you but where is the diagram
Answer
Pls the diagram and the calculations are not clear to me pls is it possible to make calculations more elaborate
Answered by
Bot
Sure, I apologize for the confusion. Here's a diagram and further elaboration on the calculations:
Let's denote the base of the radio mast as point B, the observation point due east as point E, the observation point due west as point W, and the top of the mast as point T.
Based on the information given, we can draw the following diagram:
```
T
|
|
| h
|
|
|
E --------- B --------- W
96m
```
We can see that the angle of elevation from E is 30°, which means that the triangle EBT is a right-angled triangle with angle BTE = 30°. We can use the tangent function to find the value of h:
tan(30°) = h/96
h = 96 * tan(30°)
h ≈ 55.4m
Now let's consider the angle of elevation from W, which is 60°. This means that the triangle BTW is also a right-angled triangle, with angle BTW = 60°. We can use the tangent function again to find the distance x between W and the base of the mast B:
tan(60°) = h/x
x = h/tan(60°)
x = 55.4m / √3
x ≈ 32m
Therefore, the distance of the second point from the base of the mast is approximately 32m.
I hope this helps! Please let me know if you have any further questions or concerns.
Let's denote the base of the radio mast as point B, the observation point due east as point E, the observation point due west as point W, and the top of the mast as point T.
Based on the information given, we can draw the following diagram:
```
T
|
|
| h
|
|
|
E --------- B --------- W
96m
```
We can see that the angle of elevation from E is 30°, which means that the triangle EBT is a right-angled triangle with angle BTE = 30°. We can use the tangent function to find the value of h:
tan(30°) = h/96
h = 96 * tan(30°)
h ≈ 55.4m
Now let's consider the angle of elevation from W, which is 60°. This means that the triangle BTW is also a right-angled triangle, with angle BTW = 60°. We can use the tangent function again to find the distance x between W and the base of the mast B:
tan(60°) = h/x
x = h/tan(60°)
x = 55.4m / √3
x ≈ 32m
Therefore, the distance of the second point from the base of the mast is approximately 32m.
I hope this helps! Please let me know if you have any further questions or concerns.
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