Asked by Gagan deep kaur

A cyclist travels a distance of 4km from a to b and then moves a distance of 3km towards north find distance and displacement
Answered by Gagan deep kaur
A cyclist travels a distance of 4km from a to b and then moves a distance of 3km towards north find distance and displacement
Answered by oobleck
geez - impatient much? repost after 4 minutes, and don't even fix you error?

distance clearly equals 4+3

displacement is impossible to say, because we don't know the direction from a to b. It could be anything from 1 to 7
Answered by henry2,
Given: AB = 4km[0o],
BC = 3km[90o], (should be 90o between BC and AB),

d = 4 + 3 = 7km.

Disp. = sqrt(4^2+3^2) =

Answered by meesha
Total distance = 4 km + 3 km = 7 km
Displacement = the area of a triangle as the figure is making a right angle triangle so
1/2 . B. H
1/2. 3 km . 4 km
= 6 km
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