half the faces are odd, and half are even
one face is 2 , so five (out of six) are not
the two rolls are separate, independent events
... this means multiply the individual probabilities
Hey can I have some help here?
My question:
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You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
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posted by Chloe
today at 4:20pm
one face is 2 , so five (out of six) are not
the two rolls are separate, independent events
... this means multiply the individual probabilities
First, let's determine the total number of outcomes when rolling a number cube twice. Since each roll has 6 possible outcomes (numbers from 1 to 6), the total number of outcomes for two rolls is 6x6 = 36.
Next, let's determine the number of favorable outcomes, i.e., the outcomes where we roll an even number followed by a number that is not 2.
For the first roll, the favorable outcomes are 2, 4, and 6 because they are the even numbers. After that, for the second roll, any number excluding 2 (1, 3, 4, 5, 6) will be a favorable outcome.
Therefore, the number of favorable outcomes is 3 (even numbers) x 5 (numbers excluding 2) = 15.
Lastly, we can find the probability by dividing the number of favorable outcomes (15) by the total number of outcomes (36). So, the probability of rolling an even number followed by a number that is not 2 is 15/36.
To simplify the fraction 15/36, you can divide both the numerator and denominator by their greatest common divisor, which is 3 in this case. Cancelling out the common factor, we get 15/36 = 5/12.
So, the probability is 5/12.