The heat in unit H produced by a battery current is directly proportional to time t and the square of the voltage v and inversely as the resistance R ,when H=120, t=2 v=24, R=80

(I) what is the law connecting the variable
(ii) calculate H when t= 3/2 v=120 and R= 60?

4 answers

H = ktV^2/R
plug in your point to find k

So, HR/tV^2 = k, is constant
You want H such that
60H/(3/2 * 120^2) = (120*80)/(2*24^2)

I don't know how to solve it

I dont no how to solve it

H = k t v 2