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How many electron (in mole) will discharge 2.0g of copper(ii)ion? (Cu=64)

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96.485 coulombs = 1 Faraday will deposit 64/2 g = 32 g Cu ion. Therefore, it will require
96,485 x 2/32 = ? coulombs or 1/16 of Faraday = 1/16 mole of electrons.

How many electron will be needed to discharge 32of copper

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