Question

The solubility of CO2 in water at 25 degree celsis and 1 atm is 0.034 mol/L . what is the solubility under atmospheric condition? Assume that CO obeys henry's law. ( the partial pressure of CO2 in air is 0.0003 ATM

Answer 1

Henry's Law :

c = k P

c = the solubility

P = the pressure

k = the constant of that particular gas


If c = k P

then

k = c / P


In this case:

c = 0.034 mol / L

P = 1 atm


k = c / P

k = 0.034 / 1

k = 0.034 mol / L ∙ atm


Now put this constant into Henry's law, but use the second pressure 0.0003 atm.

c = k P

c = ( 0.034 mol / L ∙ atm ) ∙ 0.0003 atm

c = 0.034 ∙ 0.0003 mol / L

c = 0.0000102 mol / L

c = 1.02 ∙ 10⁻⁵ mol / L

Answer 2

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