Asked by jacob
a boat took 5 hours to travel 60 km up a river, against the current. the return trip took 3 hours. find the speed of the boat in still water and the speed of the current.
if possible, show your steps
if possible, show your steps
Answers
Answered by
Reiny
speed of boat in still water ---- x km/h
speed of current ---- y km/h
effective speed with the current = x+y km/h
effective speed against the current = x-y km/h
time to go 60 km against the current = 60/(x-y) hours = 5
5x - 5y = 60 or <b>x - y = 12</b>
time to go 60 km with the current = 60/(x+y) = 3
3x + 3y = 60 or <b>x + y = 20</b>
solve for x and y, (add the two equation to start)
time to go 60 km with the current = 60/(x-y) hours
60/(x+y) + 60/(x-y) =
speed of current ---- y km/h
effective speed with the current = x+y km/h
effective speed against the current = x-y km/h
time to go 60 km against the current = 60/(x-y) hours = 5
5x - 5y = 60 or <b>x - y = 12</b>
time to go 60 km with the current = 60/(x+y) = 3
3x + 3y = 60 or <b>x + y = 20</b>
solve for x and y, (add the two equation to start)
time to go 60 km with the current = 60/(x-y) hours
60/(x+y) + 60/(x-y) =
Answered by
henry2,
Eq1: Vb - Vc = 60/5 = 12km/hr,
Eq2: Vb + Vc = 60/3 = 20 km/hr,
Add Eq1 and Eq2:
Vb - Vc = 12,
Vb + Vc = 20,
sum: 2Vb = 32,
Vb = 16 km/hr = Speed of the boat in still water,
Vb + Vc = 20,
16 + Vc = 20,
Vc = ?.
Eq2: Vb + Vc = 60/3 = 20 km/hr,
Add Eq1 and Eq2:
Vb - Vc = 12,
Vb + Vc = 20,
sum: 2Vb = 32,
Vb = 16 km/hr = Speed of the boat in still water,
Vb + Vc = 20,
16 + Vc = 20,
Vc = ?.
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