Asked by Anon
Nine years ago Sally was three times older Bob. In eight years time, the sum of their ages will be 78. What are their current ages?
Answers
Answered by
oobleck
if their ages now are s and b, then we are told that
s-9 = 3(b-9)
s+8 + b+8 = 78
Now just solve for s and b.
s-9 = 3(b-9)
s+8 + b+8 = 78
Now just solve for s and b.