Question

A two digit numbers is three times the sum of the digits. It is 45 less than the number formed when the digits are interchanged. Find the two digits

Please anyone to help me with solution

Answer 1

let AB be the number. Then
10A+B=3(A+B) or 7A-2B=0
10B+A-45=10A+B or 9A-9B=-45

7A-2B=0
9A-9B=-45 Now, solving that (multipy second by 7 and first by 9)
63A-18B=0
63A-63B=-315
subtract second eq from first.
-18B+63B=315
45B=315
B=7
you solve for A

Answer 2

Let the number be written as ab
Then its value is 10a+b
So, now we are told that
10a+b = 3(a+b)
10a+b = 10b+a - 45
Now just crank it out

Answer 3

Please that 10a + b where is it come from in reference to question?

Answer 4

consider the number 47
The digits are 4,7
its value is 10*4 + 7
better review base-10 numbers

a 3-digit number abc has the value 100a+10b+c
and so on