Asked by damilous
write down the binomia expansion of (1+y)^8 where y=x+x² as far as the term x^6
Answers
Answered by
Reiny
(1+y)^8 , for y = x+x^2
= 1 + 8y + 28y^2 + 56y^3 + 70y^4 + 56y^5 + 70y^6 + ..
= 1 + 8(x+x^2) + 28(x+x^2)^2 + 56(x+x^2)^3 + 70(x+x^2)^6 + ...
( the remaining terms will contain x^7 and higher )
= take over, take care in the expansions
or
look up trinomial expansion here:
https://www.qc.edu.hk/math/Advanced%20Level/Trinomials.htm
= 1 + 8y + 28y^2 + 56y^3 + 70y^4 + 56y^5 + 70y^6 + ..
= 1 + 8(x+x^2) + 28(x+x^2)^2 + 56(x+x^2)^3 + 70(x+x^2)^6 + ...
( the remaining terms will contain x^7 and higher )
= take over, take care in the expansions
or
look up trinomial expansion here:
https://www.qc.edu.hk/math/Advanced%20Level/Trinomials.htm
Answered by
damilous
great! i am very happy with this.... i will make sure i study it well
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.