Question
Graph a circle that has its center at (0,0) and passes through (2,2). Please help ASAP!!! :( I don't know how to do this!!!
Answers
Bosnian
The equation of a circle with center ( 0 , 0 ) and radius r is given by :
x² + y² = r²
In this case:
x = 2 , y = 2
x² + y² = r²
2² + 2² = r²
4 + 4 = r²
8 = r²
r = √ 8
r = √ 4 ∙ 2
r = √ 4 ∙ √ 2
r = 2 ∙ √ 2
r = 2 ∙ 1.41
r = 2.82
Draw a circles centered at the origin ( 0 , 0 ) with radius r = 2.82 and mark points x = 2 , y = 2
If you want to see graph go on:
wolframalpha.c o m
When page be open in rectangle paste this:
and click
=
x² + y² = r²
In this case:
x = 2 , y = 2
x² + y² = r²
2² + 2² = r²
4 + 4 = r²
8 = r²
r = √ 8
r = √ 4 ∙ 2
r = √ 4 ∙ √ 2
r = 2 ∙ √ 2
r = 2 ∙ 1.41
r = 2.82
Draw a circles centered at the origin ( 0 , 0 ) with radius r = 2.82 and mark points x = 2 , y = 2
If you want to see graph go on:
wolframalpha.c o m
When page be open in rectangle paste this:
and click
=
Bosnian
go on:
wolframalpha.c o m
When page be open in rectangle paste this:
image a circle center at (0,0) and passes through (2,2)
and click =
wolframalpha.c o m
When page be open in rectangle paste this:
image a circle center at (0,0) and passes through (2,2)
and click =