Asked by ted
A 33.4 g sample of a nonelectrolyte was dissolved is 680. g of water. The solution's freezing point was -2.89°C. What is the molar mass of the compound?
Answers
Answered by
DrBob222
delta T = Kf*molality
2.89 = 1.86*m
Solve for m.
Then m = mols/kg solvent. You know m and kg solvent, substitute and solve for mols.
Then mols = g/molar mass. You know mols and g, solve for molar mass.
Post your work if you get stuck.
2.89 = 1.86*m
Solve for m.
Then m = mols/kg solvent. You know m and kg solvent, substitute and solve for mols.
Then mols = g/molar mass. You know mols and g, solve for molar mass.
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.