Asked by Rebecca.
simplify 213 in base 4 multiply by 23 in base 4?
Answers
Answered by
Reiny
213 in base 4 ---> 2(4^2) + 1(4) + 3 = 39 base 10
23 in base 4 ----> 2(4) + 3 = 11
then 11*39 = 429
429 = 6(64) + 2(16) + 3(4) + 1
= 6(4^3) + 2(4^2) + 3(4) + 1
= 6231 in base 4
Unless you create yourself an addition table
and a multiplication table in base 4, the above method
is probably your best bet.
If you have the tables, you can do the calculation using
our standard algorithm for multiplication
23 in base 4 ----> 2(4) + 3 = 11
then 11*39 = 429
429 = 6(64) + 2(16) + 3(4) + 1
= 6(4^3) + 2(4^2) + 3(4) + 1
= 6231 in base 4
Unless you create yourself an addition table
and a multiplication table in base 4, the above method
is probably your best bet.
If you have the tables, you can do the calculation using
our standard algorithm for multiplication
Answered by
Reiny
oops, of course there is no 6 in base 4, my bad
so 429 in base 4
= 1(256) + 2(64) + 2(16) + 3(4) + 1
= 12231 in base 4
so 429 in base 4
= 1(256) + 2(64) + 2(16) + 3(4) + 1
= 12231 in base 4
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