Asked by Kevin
                Tan theta over 1 + sec theta + 1 +sec theta over Tan theta= 2 csc theta
            
            
        Answers
                    Answered by
            Kevin
            
    Verify the identity:
    
                    Answered by
            Reiny
            
    totally confusing the way you typed.
Lucky that I know the relation is supposed to say:
tanθ/(1+secθ) + (1+secθ)/tanθ = 2cscθ
LS = (tan^2 θ + (1+secθ)^2)/(tanθ(1+secθ)) , using a common denominator
= (tan^2 θ + 1 + 2secθ + sec^2 θ)((tanθ(1+secθ))
= (sec^2 θ - 1 + 1 + 2secθ + sec^2 θ)/(tanθ(1+secθ))
= 2secθ(secθ + 1)/(tanθ(1+secθ))
= 2secθ/tanθ , secθ ≠ -1
= 2(1/cosθ)(cosθ/sinθ)
= 2/sinθ
= 2cscθ
= RS
    
Lucky that I know the relation is supposed to say:
tanθ/(1+secθ) + (1+secθ)/tanθ = 2cscθ
LS = (tan^2 θ + (1+secθ)^2)/(tanθ(1+secθ)) , using a common denominator
= (tan^2 θ + 1 + 2secθ + sec^2 θ)((tanθ(1+secθ))
= (sec^2 θ - 1 + 1 + 2secθ + sec^2 θ)/(tanθ(1+secθ))
= 2secθ(secθ + 1)/(tanθ(1+secθ))
= 2secθ/tanθ , secθ ≠ -1
= 2(1/cosθ)(cosθ/sinθ)
= 2/sinθ
= 2cscθ
= RS
                    Answered by
            oobleck
            
    extra credit: During Reiny's proof, he came to the step where he noted
= 2secθ/tanθ , secθ ≠ -1
Are there any other values you need to watch out for ?
    
= 2secθ/tanθ , secθ ≠ -1
Are there any other values you need to watch out for ?
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.