Question
A bag contains green,yellow and black marbles.A marble is chosen at random.
The probability of choosing a yellow marble or a green marble is 0.68.
What is the probability of choosing:
a)a green marble b)a black marble c)a red marble?
The probability of choosing a yellow marble or a green marble is 0.68.
What is the probability of choosing:
a)a green marble b)a black marble c)a red marble?
Answers
Spare coochie please
+Also the probability of choosing a yellow marble is 0.26
oobleck
well, if P(y|g) = 0.68, then P(b) = 0.32
P(y|g) = P(y)+P(g), so P(g) = 0.68-0.26 = 0.42
as for P(red), who knows? You said the bag had green, yellow, and black marbles. P(r) = 0?
P(y|g) = P(y)+P(g), so P(g) = 0.68-0.26 = 0.42
as for P(red), who knows? You said the bag had green, yellow, and black marbles. P(r) = 0?