Asked by Lazarus Joseph

The spiral spring of a spring balance is 25.0cm long when 5N hangs on it as and 30.0cm long when the weight is 10N
What is the length of the spring
If the weight is 3N assuming hooke's law is obeyed?
Answered by R_scott
extension is proportional to the force

5 N extends the spring 5 cm ... 1 N/cm

relaxed length is 20.0 cm

spring is 23.0 cm with a 3 N weight
Answered by henry2,
k = (10N-5N)/(30cm-25cm) = 5N/5cm = 1N/cm . = spring constant.

Lo + (1cm/N * 5N) = 25.
Lo + 5 = 25,
Lo = 20 cm = Initial length.

L = Lo + (1cm/N * 3N) = 20 + 3 = 23 N. = Length with 3N-Wt.

Answered by Adesanya
Its okay that was an assignment
Bravoooooo
Answered by Doris nasu Bockarie
Well it's really good 👍





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