Asked by Cathy bensπ
Simplify 1/β3+2 in the form of a+bβ3?
Answers
Answered by
oobleck
rationalize the denominator
1/(2+β3) * (2-β3)/(2-β3) = (2-β3)/(2^2-3) = 2-β3
1/(2+β3) * (2-β3)/(2-β3) = (2-β3)/(2^2-3) = 2-β3
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