Asked by Anonymous
A compound which contains only carbon, hydrogen, and sulfur is burned in oxygen under such conditions that the individual volumes of the reactants and products can be measured at the same temperature and pressure. it is found that 3 volumes of the compound react with oxygen to yield 3 volumes of carbon dioxide, 3 volumes of sulfur dioxide, and 6 volumes of water vapor. What is the formula of the compound? Is this an empirical or a molecular formula?
Answers
Answered by
DrBob222
3CxHySz + 9O2 ==> 3CO2 + 3SO2 + 6H2O OR
1CxySz + 9/2 O2 ==> 1 CO2 + 1SO2 + 2H2O
CH2S emirical formula.
1CxySz + 9/2 O2 ==> 1 CO2 + 1SO2 + 2H2O
CH2S emirical formula.
Answered by
Doc48
Assuming all of the carbon, hydrogen, oxygen and sulfur come from the reactants given and n-volumes means 'molar' volumes, then ...
CₓHᵥSₑ + 9O₂ => 3CO₂ + 6H₂O + 3SO₂
=> C₃H₁₂S₃ + 9O₂ => 3CO₂ + 6H₂O + 3SO₂
=> Empirical Formula => CH₄S
CₓHᵥSₑ + 9O₂ => 3CO₂ + 6H₂O + 3SO₂
=> C₃H₁₂S₃ + 9O₂ => 3CO₂ + 6H₂O + 3SO₂
=> Empirical Formula => CH₄S
Answered by
Doc48
Oops! miss read question... '3'Vm of compound reacts... Dr Bob's solution is correct.
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