Asked by Anonymous
Write an expression for the equilibrium constant for the formation of two moles of ammonia gas (NH3) from nitrogen
and hydrogen in their standard states.
N2(g) + 3 H2(g) 2 NH3(g)
and hydrogen in their standard states.
N2(g) + 3 H2(g) 2 NH3(g)
Answers
Answered by
DrBob222
I assume this this the equation.
N2(g) + 3H2(g) ==> 2NH3(g)
Remember, equilibrium constant is product of the products divided by product of the reactants, each raised to the power indicated by the coefficients.
So Keq = (NH3)^2/(N2)(H2)^3
N2(g) + 3H2(g) ==> 2NH3(g)
Remember, equilibrium constant is product of the products divided by product of the reactants, each raised to the power indicated by the coefficients.
So Keq = (NH3)^2/(N2)(H2)^3