Asked by Abas

A drop of oil volume 10^-10m^3 spreads out on water to make a circular firm of radius 10^-1.what is the thickness of the firm.

Answers

Answered by DrBob222
Volume = pi^r^2*h

You know the volume and the radius from the problem Substitute and solve for h. (the thickness)
Answered by blessing
yes

Answered by Anonymous
Give the explanation
Of the first one
Answered by Eniola peter
Please answer this question
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