Question

I really need the answers to these few questions I just can't figure these out pls help!!

Find the solutions to each quadratic trinomial by factoring.
5) x2 + 4x - 12 =0

6) x2 - 8x + 15 =0

7) x2 + x - 72 =0

8) x2 - 4x + 4 = 0

9) 2x2 + 6x - 8= 0 (HINT: factor the GCF first!)

Answer 1

Do you mean
2x or 2^2?

2 times x or 2 to the 2nd power?

Answer 2

Online "^" is used to indicate an exponent, e.g., x^2 = x squared.

We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.

However, I will do one for you. Factor the -12. It can give you 2*6 or 3*4. However, to get the 4 and the -12, you would need 6 and -2.

Therefore, x2 + 4x - 12 =0 leads to (x-2)(x+6).

I hope this helps.

Answer 3

5. x^2 + 4x - 12 = 0.
-12 = -1*12 = -2*6.
Select the pair of factors whose sum equals B:
-2 + 6 = 4 = B.
(x-2)(x+6) = 0.
x-2 = 0, X = 2.
x + 6 = 0, X = -6.
Solution: X = 2, and -6.

6. x^2 - 8x + 15 = 0.
15 = (-1)*(-15) = (-3)*(-5). Choose (-3) and (-5) because their sum = B.
(x-3)(x-5) = 0.
x-3 = 0, X = 3.
x-5 = 0, X = 5.
Solutions: = X = 3, and 5.