Question
Five men and four women are waiting to be interviewed for jobs. If they are all selected in random​ order, find the probability that no man will be interviewed until at least two women have been interviewed.
Answers
We must exclude the cases where the
first two are MW and MM
with no restriction, the number of ways to arrange the interviews is
9!/(4!5!) = 126
case of MM = 7!/(3!4!) = 35
case of MF = 7!/(4!3!) = 35
Prob(your stated event) = 1 - 70/126 = 4/9
first two are MW and MM
with no restriction, the number of ways to arrange the interviews is
9!/(4!5!) = 126
case of MM = 7!/(3!4!) = 35
case of MF = 7!/(4!3!) = 35
Prob(your stated event) = 1 - 70/126 = 4/9
answer ' =55