Asked by QUIK MATHS
Bob's age in 10 years will be the same as Peggy’s age is now. Five years from now, Peggy’s age will be twice Ellis age. What are their present ages?
Answers
Answered by
QUIK MATHS
Is the equation b+10=p?
Answered by
oobleck
yes,
b+10 = p
But also,
p+5 = 2e
Not sure who the heck Ellis is, but if you meant Bob, then we have
p+5 = 2(b+5)
or, rearranging things,
p - 2b = 5
p - b = 10
subtracting, we get
b = 5
So,
Bob is 5 and Peggy is 15
In 5 years, they will be 10 and 20
b+10 = p
But also,
p+5 = 2e
Not sure who the heck Ellis is, but if you meant Bob, then we have
p+5 = 2(b+5)
or, rearranging things,
p - 2b = 5
p - b = 10
subtracting, we get
b = 5
So,
Bob is 5 and Peggy is 15
In 5 years, they will be 10 and 20
Answered by
henry2,
Bob's age = X.
Peggy's age = x+10.
Difference = x+10 - x = 10 years.
5 yrs. from now:
Peggy's age = x+15.
Bob's age = (x+15)/2.
The difference between their ages is still = 10 yrs.
(x+15) - (x+15)/2 = 10.
2x + 30 -x - 15 = 20,
X = 5 Years = Bob's present age.
x+10 = 5+10 = 15 years = Peggy's present age.
Peggy's age = x+10.
Difference = x+10 - x = 10 years.
5 yrs. from now:
Peggy's age = x+15.
Bob's age = (x+15)/2.
The difference between their ages is still = 10 yrs.
(x+15) - (x+15)/2 = 10.
2x + 30 -x - 15 = 20,
X = 5 Years = Bob's present age.
x+10 = 5+10 = 15 years = Peggy's present age.
Answered by
Arya
THX
Answered by
wutdoidowithlifeeeeeeeeeeeeeeeee
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Answered by
urmumisfat
your fat
Answered by
Rishi
Thank you henry2
Answered by
Super Oink
Thx Henry 2
Bob= 5 years old
Peggy= 15 years old
Bob= 5 years old
Peggy= 15 years old
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