Asked by sweetiepie
In a carnival fishing game, the player is given a net to catch plastic fish. The player is allowed to scoop up 4 fish from a pool containing 36 fish, one of which is the winning fish. What is the probability of winning the game?
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I am having a hard time with probability and struggling with what steps to do.
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I am having a hard time with probability and struggling with what steps to do.
Answers
Answered by
Damon
probability of winning = 1 - probability of losing
none on first scoop = 35/36
now you have 35 in there
none on second scoop = 34/35
none on third scoop = 33/34
none on fourth scoop = 32/33
so probability of getting NONE in 4 scoops
= 35/36 * 34/35 * 33/34 * 32/33
so
1 - that
none on first scoop = 35/36
now you have 35 in there
none on second scoop = 34/35
none on third scoop = 33/34
none on fourth scoop = 32/33
so probability of getting NONE in 4 scoops
= 35/36 * 34/35 * 33/34 * 32/33
so
1 - that
Answered by
sweetiepie
Oh, so this is a dependent event. Thank you! :)
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