Asked by Princess
A boy walks 1260meters on a bearing of 120°.how far South is he from the starting point?show all workings including drawing
Answers
Answered by
Reiny
In my sketch I have a triangle in the 4th quadrant with a hypotenuse of 1260 and
a base angle of 30° trying to find the y value
sin30° = y/1260
y = 1260sin39° metres.
Be careful how you word your answer, remember that your value is negative
in quadrant 4. However, if you use the word "south" you don't show the negative sign.
a base angle of 30° trying to find the y value
sin30° = y/1260
y = 1260sin39° metres.
Be careful how you word your answer, remember that your value is negative
in quadrant 4. However, if you use the word "south" you don't show the negative sign.
Answered by
henry2,
All angles are measured CW from +Y-axis.
1260m[120o] = distance traveled.
Y = 1260*Cos120 = -630 = 630 m., South.
for CW rotation(bearing), we are in Q2.
1260m[120o] = distance traveled.
Y = 1260*Cos120 = -630 = 630 m., South.
for CW rotation(bearing), we are in Q2.
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