Asked by adi
Consider the following equation:
4 NH3 (g) + 5 O2(g) 4 NO (g) + 6 H2O(g)
(a) How many liters of oxygen are required to react with 2.5 L NH3 ? Both gases are at STP.
4 NH3 (g) + 5 O2(g) 4 NO (g) + 6 H2O(g)
(a) How many liters of oxygen are required to react with 2.5 L NH3 ? Both gases are at STP.
Answers
Answered by
DrBob222
When gases are involved one may use a short cut in which L are used as if they were mols.
4 NH3 (g) + 5 O2(g) 4 NO (g) + 6 H2O(g)
Therefore, 2.5 L x (5 mols O2/4 mols NH3) = ? L O2
4 NH3 (g) + 5 O2(g) 4 NO (g) + 6 H2O(g)
Therefore, 2.5 L x (5 mols O2/4 mols NH3) = ? L O2
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