Question
A chemist has a solution of NaOH 4 mol/L and wishes to prepare 500 mL of a
Solution at 3 mol/L. What volume should it use from the 4 mol/L solution?
Solution at 3 mol/L. What volume should it use from the 4 mol/L solution?
Answers
R_Scott
500 mL of a 3 M solution contains 1.5 moles of solute
volume = 1.5 moles / (4 mol/L)
volume = 1.5 moles / (4 mol/L)
Sydney :)
R_Scott is right in my opinion
DrBob222
You may use the dilution formula, also, which is
mL1 x M1 = mL2 x M2
mL1 x 4M = 500 x 3M
Then mL of the 4M = 500 x 3/4 = ?
mL1 x M1 = mL2 x M2
mL1 x 4M = 500 x 3M
Then mL of the 4M = 500 x 3/4 = ?