Asked by Anonymous
if 465cm cube of so2 can diffuse through a porous partition in 30sec how long will (a) an equal volume (b) 630cm cube of hydrogen sulphide take to diffuse through the same partition
Answers
Answered by
DrBob222
rate SO2 = volume/time = 465 cc/30 sec = ?
rate H2S = 465/time
MM = molar mass
(rate SO2/rate H2S) = sqrt(MM H2S/MMSO2)
Plug in and solve for time H2S
Do the same for part b but substitute 630 cc for volume H2S.
Post your work if you get stuck.
rate H2S = 465/time
MM = molar mass
(rate SO2/rate H2S) = sqrt(MM H2S/MMSO2)
Plug in and solve for time H2S
Do the same for part b but substitute 630 cc for volume H2S.
Post your work if you get stuck.
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