Asked by Kd
find the two possible of x if 10sinx = 6 and 0 <=x<=180
sinx = 3/5
x = sin^-1(.6)
sinx = 3/5
x = sin^-1(.6)
Answers
Answered by
Bosnian
sin x = 6 / 10 = 3 / 5
First solution:
x = sin^-1 (0.6) = sin^-1 ( 3 / 5 )
x = 36.86989765°
Second solution:
Use identity:
sin ( 180° - x ) = sin x
sin ( 180° - 36.86989765° ) = 3 / 5
sin ( 143.13010235°) = 3 / 5
First solution:
x = sin^-1 (0.6) = sin^-1 ( 3 / 5 )
x = 36.86989765°
Second solution:
Use identity:
sin ( 180° - x ) = sin x
sin ( 180° - 36.86989765° ) = 3 / 5
sin ( 143.13010235°) = 3 / 5
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