Asked by ben
⦁ Sand is being poured on the ground from the office of an elevated pipe. It forms a conical pile whose altitude is always equal to 4/3 the radius of the base. Approximate all the answers to two decimal places.
⦁ How fast is the volume increasing when the radius of the base is 4 feet and is increasing at the rate of 0.01 ft. /s?
⦁ If sand is falling at the rate of 5 cubic ft. / s., how fast is the radius of the pile increasing when the radius is 5 feet?
Answers
Answered by
R_Scott
V = 1/3 π r^2 h = 1/3 * π * r^2 * (4 r / 3) = (4 π / 9) * r^3
implicit differentiation ... dV = (4 π / 9) * 3 r^2 dr = (4 π / 3) * r^2 dr
use the equation by plugging in known (given) values and solving
implicit differentiation ... dV = (4 π / 9) * 3 r^2 dr = (4 π / 3) * r^2 dr
use the equation by plugging in known (given) values and solving
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