Asked by Anonymous
Molefraction of water in sulphuric acid solution us 0.85 calculate the molality of the solution
Answers
Answered by
DrBob222
Assume 1 mol total which means
0.85 mols H2O x (18 g H2O/1 mol H2O) = about 15.3 g H2O
0.15 mols H2SO4 x (98 g H2SO4/1 mol H2SO4) = about 14.7 g H2SO4
Total = about 30 grams or 0.03 kg solution
m H2SO4 = mols H2SO4/kg solution = 0.15/0.03 = ?
0.85 mols H2O x (18 g H2O/1 mol H2O) = about 15.3 g H2O
0.15 mols H2SO4 x (98 g H2SO4/1 mol H2SO4) = about 14.7 g H2SO4
Total = about 30 grams or 0.03 kg solution
m H2SO4 = mols H2SO4/kg solution = 0.15/0.03 = ?