Question
The weight of an object varies inversely as the square of its distance from the centre of the earth. The weight of an aeroplane is observed to be only 4/9 of its weight on earth. How far is the aeroplane from the surface of the earth. Take the radius of the earth to be 6400km
Answers
aeroplane ... or space capsule?
inverse square root of 3/2
(3/2 * 6400) - 6400
inverse square root of 3/2
(3/2 * 6400) - 6400
woof ... not fully awake yet
inverse square root of 4/9 is 3/2
(3/2 * 6400) - 6400 = ?
inverse square root of 4/9 is 3/2
(3/2 * 6400) - 6400 = ?
W=k/d^2.
Distance = r+R.
Distance from the centre, r=0
W=k/R×R
K =W×R×R
W=w×R×R/(r+R)^2
4W/9=(W×R×R)/(r+R)^2
4W(r+R)^2= 9×W×R×R
4(r+R)^2=9×R×R
(r+6400)^2= 9×6400×6400/4
r+6400= 9600
r = 9600-6400
r=3200km
Distance = r+R.
Distance from the centre, r=0
W=k/R×R
K =W×R×R
W=w×R×R/(r+R)^2
4W/9=(W×R×R)/(r+R)^2
4W(r+R)^2= 9×W×R×R
4(r+R)^2=9×R×R
(r+6400)^2= 9×6400×6400/4
r+6400= 9600
r = 9600-6400
r=3200km
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