Asked by Agbozo

The weight of an object varies inversely as the square of its distance from the centre of the earth. The weight of an aeroplane is observed to be only 4/9 of its weight on earth. How far is the aeroplane from the surface of the earth. Take the radius of the earth to be 6400km

Answers

Answered by R_Scott
aeroplane ... or space capsule?

inverse square root of 3/2

(3/2 * 6400) - 6400
Answered by R_Scott
woof ... not fully awake yet

inverse square root of 4/9 is 3/2

(3/2 * 6400) - 6400 = ?
Answered by Addo
W=k/d^2.
Distance = r+R.
Distance from the centre, r=0
W=k/R×R
K =W×R×R
W=w×R×R/(r+R)^2
4W/9=(W×R×R)/(r+R)^2
4W(r+R)^2= 9×W×R×R
4(r+R)^2=9×R×R
(r+6400)^2= 9×6400×6400/4
r+6400= 9600
r = 9600-6400
r=3200km


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