Question

Solve the system of equations algebraically. Show all of your steps.

y=x^2+2x
**y=x^2+2x
(2/2)^2=1
1=answer**

y=3x+20
**y=3x+20
(3/2)^2=2.25
2.25=answer**

am i right or wrong, if im wrong could someone show me the steps

Answer 1

the system of equations is
y=x^2+2x
y=3x+20
You want to find a value of x that makes both equations true. So, since the expressions must be equal,
x^2 + 2x = 3x + 20
x^2 - x - 20 = 0
(x-5)(x+4) = 0
x = 5 or -4

check:
5^2 + 2*5 = 35
3*5 + 20 = 35

(-4)^2 + 2(-4) = 16-8 = 8
3(-4)+20 = -12+20 = 8

So, yes, both values are solutions to both equations

Answer 2

1.b
2.b
3.d
4.c
5.b
6.a
7.a
8.b
9.b
10.b
11.c
12.a
13.b
14.c
15.c
16.c
17.b
18.b
19.d
20.b
21.c

Answer 3

First off that's the test answers for Unit 5 Lesson 10, to add the answers listed are also incorrect