Asked by Sophia
A bag has 2 red marbles, 1 blue marble and 4 gold marbles. What is the probability of drawing two gold marbles, if the first marble is replaced after it is drawn?
C. 4/7
D. 7/13
( I didn't add A or B `cause i knew those were wrong)
C. 4/7
D. 7/13
( I didn't add A or B `cause i knew those were wrong)
Answers
Answered by
Reiny
since you are replacing the marble the two events are independent, so multiply the two probs.
What is the prob(drawing a red) ?
so prob(2 reds - with replacement) = (4/7)(4/7) = 16/49
(perhaps one of the choices you rejected)
What is the prob(drawing a red) ?
so prob(2 reds - with replacement) = (4/7)(4/7) = 16/49
(perhaps one of the choices you rejected)
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