Asked by Anonymous
A saturated solution of salt x contain 0.28g of the salt in 100cm^3 of solution at 25°c what is the solubility of the salt in (i) mom/dm^3 (II)g/dm^3
Answers
Answered by
DrBob222
0.28 g/100 cc x (1000 cc/dm^3) = ? g/dm^3
You don't have enough information to calculate mols/dm^3. You need the molarmass of the salt x to do that.
You don't have enough information to calculate mols/dm^3. You need the molarmass of the salt x to do that.
Answered by
Sam
Reviev the question for me
Answered by
Sam
I want to know how you get that answer
Answered by
Destiny
First what is the formula for solubility
which is given massof the solute ×1000÷molar mass of the solute ÷volume of the solvent
I know the problem is the RMM (relative molecular mass )
But relative molecular mass is the same has molar mass
so our given mass of the solute is 0.28 ×1000÷56÷100
=0.05mol dm^-3
which is given massof the solute ×1000÷molar mass of the solute ÷volume of the solvent
I know the problem is the RMM (relative molecular mass )
But relative molecular mass is the same has molar mass
so our given mass of the solute is 0.28 ×1000÷56÷100
=0.05mol dm^-3
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