Asked by Bill

Find the exact area of the region that lies beneath the curve y = 3(x^[1/3]) 0 ≤ x ≤ 27
Answered by oobleck
that would, of course, be
∫[0,27] 3x^(1/3) dx
Answered by Anonymous
find the exact area of the region that lies beneath the curve y=6cubesqrtx 0≤x≤27
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