Question
Find the exact area of the region that lies beneath the curve y = 3(x^[1/3]) 0 ≤ x ≤ 27
Answers
oobleck
that would, of course, be
∫[0,27] 3x^(1/3) dx
∫[0,27] 3x^(1/3) dx
Anonymous
find the exact area of the region that lies beneath the curve y=6cubesqrtx 0≤x≤27