Question

find the solutions to the system
y=x^2+5x=6
y=4x=12

A( 2,20) and (-3,0)
B (2,20) and (-3,18)
C(-2,-10) and (-3,-18)
D no solutions

Answer 1

some of those = signs are probably +
which ones?

then, show us your work at solving the system ...

Or heck, just try plugging in the 3 points to see which on works, if any.

Answer 2

Y = x^2 + 5x + 6.
Y = 4x + 12.

4x + 12 = x^2 + 5x + 6.
x^2 + x - 6 = 0. -6 = -2 * 3. sum = -2 + 3 = 1 = B.
(x-2)(x+3) = 0.
x - 2 = 0, X = 2.
x + 3 = 0, X = -3.

When X = 2, Y = 4x + 12 = 4*2 + 12 = 20. (2, 20).
When X = -3, Y = 4x + 12 = 4*(-3) + 12 = 0. (-3, 0).

Answer 3

y = x^2+5x+6 = (x+2)(x+3)
y = 4x+12 = 4(x+3)
so, 4(x+3) = (x+2)(x+3)
4 = x+2 or 0 = x+3
...