Asked by Cathrine
A copper sphere of a radius 5 cm is immersed inside a cylindrical container.If the base radius of the container is 7 cm, find the rise in water level, correct to 1 decimal place
Answers
Answered by
R_scott
sphere volume = π * r^2 * (water level rise)
4/3 * π * 5^3 = π * 7^2 * (rise)
4/3 * π * 5^3 = π * 7^2 * (rise)
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